(5x+7)(2x^2+4x+1)=

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Solution for (5x+7)(2x^2+4x+1)= equation:


Simplifying
(5x + 7)(2x2 + 4x + 1) = 0

Reorder the terms:
(7 + 5x)(2x2 + 4x + 1) = 0

Reorder the terms:
(7 + 5x)(1 + 4x + 2x2) = 0

Multiply (7 + 5x) * (1 + 4x + 2x2)
(7(1 + 4x + 2x2) + 5x * (1 + 4x + 2x2)) = 0
((1 * 7 + 4x * 7 + 2x2 * 7) + 5x * (1 + 4x + 2x2)) = 0
((7 + 28x + 14x2) + 5x * (1 + 4x + 2x2)) = 0
(7 + 28x + 14x2 + (1 * 5x + 4x * 5x + 2x2 * 5x)) = 0
(7 + 28x + 14x2 + (5x + 20x2 + 10x3)) = 0

Reorder the terms:
(7 + 28x + 5x + 14x2 + 20x2 + 10x3) = 0

Combine like terms: 28x + 5x = 33x
(7 + 33x + 14x2 + 20x2 + 10x3) = 0

Combine like terms: 14x2 + 20x2 = 34x2
(7 + 33x + 34x2 + 10x3) = 0

Solving
7 + 33x + 34x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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